# If a spring has a constant of 3 (kg)/s^2, how much work will it take to extend the spring by 83 cm ?

The work is given by the formula $W = \frac{1}{2} k {x}^{2}$
$k = \text{spring constant} = 3 k \frac{g}{s} ^ 2$
$x = \text{displacement} = 83 c m = \frac{83}{100} m = 0.83 m$
$W = \frac{1}{2} \left(3\right) . {\left(0.83\right)}^{2} J$
$W = 1.03 J$