# If a spring has a constant of 4 (kg)/s^2, how much work will it take to extend the spring by 29 cm ?

Apr 7, 2018

so to calculate the work you need the equation that goes:
$W = \frac{1}{2} \cdot k \cdot {x}^{2}$
with $k$ being the hook constant, $x$ is the distance and $W$ is the work needed

so

$W = \frac{1}{2} \cdot 4 \cdot {\left(29 \cdot {10}^{- 2}\right)}^{2}$

$\Rightarrow W = 0.1682 J$

P.S. I hope you mean that $k = 4 \frac{k g}{m} ^ 2$