Question

If a spring has a constant of `4 (kg)/s^2`, how much work will it take to extend the spring by `41 cm`?

Answer 1

`E_p=W=0,34J`

Explanation:

`E_p=1/2*K*Delta x^2`

`Delta x=41cm=0,41m`

`K=4kg/s^2`

`E_p:"Potential energy for the extended spring"`

`W:"Work"`

`E_p=W=1/2*4*(0,41)^2`

`E_p=W=2*0,17`

`E_p=W=0,34J`