If a spring has a constant of 4 (kg)/s^2, how much work will it take to extend the spring by 3 cm ?

Apr 12, 2016

$W = {E}_{p} = 18 \cdot {10}^{-} 4 J$

Explanation:

$W : \text{work}$
${E}_{p} : \text{the stored energy for spring}$
$K : \text{spring constant}$
$\Delta x = 3 \text{ cm=0,03 m}$
$W = {E}_{p} = \frac{1}{2} \cdot K \cdot \Delta {x}^{2}$
$W = {E}_{p} = \frac{1}{2} \cdot 4 \cdot {\left(0 , 03\right)}^{2}$
$W = {E}_{p} = 2 \cdot 0 , 0009$
$W = {E}_{p} = 18 \cdot {10}^{-} 4 J$