Question

If a spring has a constant of `4 (kg)/s^2`, how much work will it take to extend the spring by `19 cm`?

Answer 1

3.04J of work.

Explanation:

19cm=0.19m

Hooke's law says that `FpropDeltax`, or `F=kDeltax`. In this question we know both the extension, and spring constant, so we just have to do 0.19x4=0.76N.

The question however asks for work done, which is represented by `W=FDeltas`, `Deltas=Deltax`. We just need to do 0.76x4=3.04J of work.