# If a spring has a constant of 6 (kg)/s^2, how much work will it take to compress the spring 7 cm ?

$w = \frac{1}{2} k {x}^{2}$,where k = spring constant
x = 7 cm=$\frac{7}{100}$m
k= 6$\frac{k g}{s} ^ 2$
$\therefore w = \frac{1}{2} \cdot 6 \cdot 7 \cdot {10}^{-} 2 = 0.21$J