# If a spring has a constant of 6 kgs^-2, how much work will it take to extend the spring by 67  cm ?

Feb 14, 2016

The work done is equal to the change in spring potential energy: ${E}_{p} = \frac{1}{2} k {x}^{2} = \frac{1}{2} \cdot 6 \cdot {0.67}^{2} = 1.35$ $J$.

#### Explanation:

There's probably not a lot more explanation needed. The work required to extend the spring is stored as spring potential energy.

We could also calculate this using $W = F d$, but because the force changes as the distance changes, this requires integrating the force over the distance, so the spring potential energy method is simpler.