# If a spring has a constant of 6 (kg)/s^2, how much work will it take to extend the spring by 43 cm ?

Feb 15, 2016

$W = {E}_{p} = 0 , 5547 J$

#### Explanation:

$\text{It has the potential energy ,if spring extends}$
$W = {E}_{p} = \frac{1}{2} \cdot k \cdot \Delta {x}^{2}$
$W = {E}_{p} = \frac{1}{2} \cdot 6 \cdot {\left(0 , 43\right)}^{2}$
$43 c m = 0 , 43 m$
$W = {E}_{p} = 3 \cdot 0 , 1849$
$W = {E}_{p} = 0 , 5547 J$