If a spring has a constant of #7 (kg)/s^2#, how much work will it take to extend the spring by #29 cm #?

1 Answer
Jan 20, 2016

Answer:

#W = int_0^29kxdx = |1/2kx^2|_0^29 = 1/2 7xx29 #

Explanation:

Work, #W = int vec F_x * vecdx = intFdx#
Now for spring the Force # F = kx # where k is spring constant
thus #W = int kx dx #
Integrate and substitute k= 7 and the spring stretch - x from 0 => 29:
#W = int_0^29kxdx = |1/2kx^2|_0^29 = 1/2 7xx29 #