Question

If a spring has a constant of `7 (kg)/s^2`, how much work will it take to extend the spring by `38 cm`?

Answer 1

`W=0,51J`

Explanation:

`"the potential energy for extended spring is given as:"`
`W=E_p=1/2*K*Delta x^2`

`"where W:work,E_p:the potential energy,K:spring constant"`
`Delta x=38 cm=0,38m`
`W=1/2*7*(0,38)^2`

`W=0,51J`