# If a spring has a constant of 7 (kg)/s^2, how much work will it take to extend the spring by 41 cm ?

Feb 27, 2017

The work is $= 0.59 J$

#### Explanation:

The work done on a spring is

$W = \frac{1}{2} k {x}^{2}$

The elongation is $x = 0.41 m$

The spring constant is $= k = 7 k g {s}^{-} 2 = 7 N {m}^{-} 1$

The work is

$W = \frac{1}{2} \cdot 7 \cdot 0.41 \cdot 0.41$

$= 0.59 J$