If a spring has a constant of #7 (kg)/s^2#, how much work will it take to extend the spring by #21 cm #?

1 Answer
Jul 23, 2017

Answer:

#0.31J#

Explanation:

#F=kDeltax#, and #W=FDeltas#, where:
#Deltax=Deltas# = extension/distance travelled in the direction of the force (#m#)
#F# = force (#N#)
#W# = Work done (#Nm#)
#k# = spring constant (#N# #m^(-1)#)

Therefore, #W=k(Deltax)(Deltax)=k(Deltax)^2=7*0.21^2=0.3087~~0.31J#