If a spring has a constant of #8 (kg)/s^2#, how much work will it take to extend the spring by #42cm #?

1 Answer
Mar 11, 2016

Answer:

#"Work="Delta E_p=0,7056" "J#

Explanation:

#"it is gains energy while spring extending"#
#"Work="Delta E_p=1/2 k Delta x^2#
#42 cm=0,42 m#
#"Work="Delta E_p=1/2*8(0,42)^2#
#"Work="Delta E_p=4*(0,42)^2#
#"Work="Delta E_p=0,7056" "J#