Question

If a spring has a constant of `9 (kg)/s^2`, how much work will it take to extend the spring by `22 cm`?

Answer 1

The work done in extending the spring a distance, e, is given by the area under the force-extension graph for the spring. This equals:
`W=1/2*F*e`
for a spring that obeys Hooke's law.

The relationship between force and extension is given by `F=k*e`
If you substitute the above into the first equation you arrive at:
`W=1/2*k*e^2`
Hence:
`W= 1/2*9*0.22^2=0.22J`