# If a volume of 22.9 mL of 0.634 M NaOH is required to react with all of the acid, what is the molar mass of the acid?

We can work out the molar equivalence of the acid, and it is simply $22.9 \times {10}^{-} 3 \cdot L \times 0.634 \cdot m o l \cdot {L}^{-} 1$...