# If an ellipse has foci (0, +-1) and vertices (0, +-2) What is the eccentricity of the ellipse?

Eccentricity $e = \frac{1}{2}$

#### Explanation:

Foci$\left(0 , \pm 1\right)$ and Vertex $\left(0 , \pm 2\right)$

$a = 2$ and $c = 1$

Eccentricity $e = \frac{c}{a} = \frac{1}{2}$

${a}^{2} = {c}^{2} + {b}^{2}$

${2}^{2} = {1}^{2} + {b}^{2}$

${b}^{2} = 3$

graph{x^2/3+y^4=1[-5,5,-3,3]}

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