# If an Ideal gas has a pressure of 9.75 atm, a temperature of 323 K, and has a volume of 33.81 L, how many moles of gas are in the sample?

Jul 1, 2016

$n = \frac{P V}{R T}$

#### Explanation:

$P$ $=$ $9.75 \cdot a t m$;

$V$ $=$ $33.81 \cdot L$

$R$ $=$ $0.0821 \cdot L \cdot a t m \cdot {K}^{-} 1 \cdot m o {l}^{-} 1$

$T$ $=$ $323 \cdot K$

You ave just got to fill in the dots to give an answer in $\text{MOLES}$

This will be inevitable dimensionally:

$\frac{\cancel{a t m} \times \cancel{K}}{\cancel{L} \cdot \cancel{a t m} \cdot \cancel{{K}^{-} 1} \cdot m o {l}^{-} 1 \times \cancel{K}}$

That is you get an answer in $\frac{1}{m o {l}^{-} 1} = m o l \text{ as required.}$

Capisce?