If an object is moving at #0 ms^-1# and accelerates to #60 ms^-1# over #24/5# seconds, what was the object's rate of acceleration?

1 Answer
Jan 15, 2016

Answer:

Using the formula #v = u + at#, the acceleration is #12.5 ms^-2#.

Explanation:

The useful formula is #v = u + at#, where #v# is the final velocity #(ms^-1)#, #u# is the initial velocity #(ms^-1)#, #a# is the acceleration #(ms^-2)# and #t# is the time #(s)#.

Rearranging, #a=(v-u)/t = (60-0)/(24/5) = 12.5 ms^-2#

{whisper}Not sure what this US obsession with fractions is all about! I guess the answer could be expressed as #25/2 ms^-2#, but why ?{/whisper}