# If an object is moving at 0 ms^-1 and accelerates to 60 ms^-1 over 24/5 seconds, what was the object's rate of acceleration?

Jan 15, 2016

#### Answer:

Using the formula $v = u + a t$, the acceleration is $12.5 m {s}^{-} 2$.

#### Explanation:

The useful formula is $v = u + a t$, where $v$ is the final velocity $\left(m {s}^{-} 1\right)$, $u$ is the initial velocity $\left(m {s}^{-} 1\right)$, $a$ is the acceleration $\left(m {s}^{-} 2\right)$ and $t$ is the time $\left(s\right)$.

Rearranging, $a = \frac{v - u}{t} = \frac{60 - 0}{\frac{24}{5}} = 12.5 m {s}^{-} 2$

{whisper}Not sure what this US obsession with fractions is all about! I guess the answer could be expressed as $\frac{25}{2} m {s}^{-} 2$, but why ?{/whisper}