Question

If an object is moving at `0 m/s` and accelerates to `90 m/s` over 8 seconds, what was the object's rate of acceleration?

Answer 1

The rate of acceleration is `=11.25ms^-2`

Explanation:

We apply the equation of motion

`v=u+at`

The initial velocity is `u=0ms^-1`

The final velocity is `v=90ms^-1`

The time is `t=8s`

The acceleration is

`a=(v-u)/t=(90-0)/8=90/8=11.25ms^-2`