# If an object is moving at 12 m/s and accelerates to 32 m/s over 3 seconds, what was the object's rate of acceleration?

Dec 11, 2015

The acceleration is $\text{7 m/s"^2}$.

#### Explanation:

$a = \frac{{v}_{f} - {v}_{i}}{\Delta t}$, where $a$ is acceleration, ${v}_{f}$ is final velocity, ${v}_{i}$ is initial velocity, and $\Delta t$ is the time interval.

Given
${v}_{i} = \text{12 m/s}$
${v}_{f} = \text{32 m/s}$
$\Delta t = \text{3 s}$

Solution
Substitute the given values into the equation.

$a = \left(32 \text{m/s"-12"m/s")/(3"s}\right)$

$a = \left(20 \text{m/s")/(3"s}\right)$

$a = \text{7 m/s"^2}$ (rounded to one significant figure)