# If an object is moving at 15 m/s and accelerates to 19 m/s over 4 seconds, what was the object's rate of acceleration?

##### 1 Answer
May 19, 2016

$a = \frac{4}{4} = 1 \text{ } \frac{m}{s} ^ 2$

#### Explanation:

${v}_{i} = 15 \frac{m}{s} \text{ initial velocity}$
${v}_{f} = 19 \frac{m}{s} \text{ final velocity}$
$t = 4 s \text{ time}$

$\text{acceleration of object is determined as :} a = \frac{\Delta V}{\Delta t}$

$\Delta v = {v}_{f} - {v}_{i} = 19 - 15 = 4$

$\Delta t = {t}_{f} - {t}_{i} = 4 - 0 = 4$

$a = \frac{4}{4} = 1 \text{ } \frac{m}{s} ^ 2$