# If an object is moving at 60 m/s and accelerates to 145 m/s over 5 seconds, what was the object's rate of acceleration?

Feb 24, 2016

The acceleration is $\text{17 m/s"^2}$.

#### Explanation:

Use the formula $a = \frac{{v}_{f} - {v}_{i}}{\Delta t}$, where $a$ is acceleration, ${v}_{i}$ is initial velocity, ${v}_{f}$ is final velocity, and $\Delta t$ is time interval.

Known
${v}_{i} = \text{60 m/s}$
${v}_{f} = \text{145 m/s}$
$\Delta t = \text{5 s}$

Unknown
$a$

Solution
Substitute the known variables into the formula and solve.

$a = \frac{{v}_{f} - {v}_{i}}{\Delta t}$

$a = \left(145 \text{m/s"-60"m/s")/(5"s}\right)$

$a = \left(85 \text{m/s")/(5"s}\right)$

$a = \text{17 m/s"^2}$