If an object with a mass of #15 kg # changes speed from #8 m/s# to #14 m/s#, by how much does its kinetic energy change?

1 Answer
Dec 11, 2015

Answer:

I found a change of #DeltaK=990J#.

Explanation:

Kinetic Energy #K# is given as:
#K=1/2mv^2#
Considering the initial and final stages of your phenomenon you have that the change in #K# will be:
#DeltaK=K_f-K_i=1/2mv_f^2-1/2mv_i^2=1/2m(v_f^2-v_i^2)=#
#=1/2*15*(14^2-8^2)=990J#