If an object with a mass of #2 kg # changes speed from #6 m/s# to #13 m/s#, by how much does its kinetic energy change?

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Answer 1 · 2018-05-01T22:30:41

#=>Delta E = 133 " J"#

Kinetic energy is given as:

#E = 1/2 m v^2#

We can compute the change by subtracting the initial from the final energy.

#Delta E = 1/2mv_f^2 - 1/2mv_i^2#

#Delta E= 1/2m(v_f^2-v_i^2)#

#Delta E = 1/2 (2)((13)^2 - (6)^2)#

#Delta E = 169 - 36#

#=>Delta E = 133 " J"#