# If an object with a mass of 2 kg  changes speed from 6 m/s to 5 m/s, by how much does its kinetic energy change?

Mar 6, 2018

$11 J$

#### Explanation:

change in KE$= \frac{1}{2} m {v}_{2}^{2} - \frac{1}{2} m {v}_{1}^{2}$

$\implies \Delta K E = \frac{1}{2} m \left({v}_{2}^{2} - {v}_{1}^{2}\right)$

$\Delta K E = \cancel{\frac{1}{2} \times 2} \left({6}^{2} - {5}^{2}\right)$

$\Delta K E = 36 - 25 = 11 J$