If an object with a mass of #5 kg # changes speed from #12m/s# to # 14m/s#, by how much does its kinetic energy change?

1 Answer
May 15, 2016

Answer:

#Delta E=130" "J#

Explanation:

#E_i=1/2*m*v_i^2" the initial kinetic energy"#

#E_f=1/2*m*v_f^2" the final kinetic energy"#

#Delta E=E_f-E_i#

#Delta E=1/2*m(v_f^2-v_i^2)#

#Delta E=1/2*5(14^2-12^2)#

#Delta E=1/2*5(196-144)#

#Delta E=1/2*5*52#

#Delta E=130" "J#