If an object with a mass of #5 kg # changes speed from #5m/s# to #16 m/s#, by how much does its kinetic energy change?

1 Answer
Dec 25, 2015

Answer:

I found #577.5N#

Explanation:

You can consider that kinetic energy #K# is given as:
#K=1/2mv^2#
So in your case:
#DeltaK=K_f-K_i=1/2mv_f^2-1/2mv_i^2=#
For the final and initial conditions. Giving:
#DeltaK=1/2m(v_f^2-v_i^2)=1/2*5(16^2-5^2)=5/2(256-25)=577.5N#