Question

If an object with a mass of `5 kg` changes speed from `5m/s` to `16 m/s`, by how much does its kinetic energy change?

Answer 1

I found `577.5N`

Explanation:

You can consider that kinetic energy `K` is given as:
`K=1/2mv^2`
So in your case:
`DeltaK=K_f-K_i=1/2mv_f^2-1/2mv_i^2=`
For the final and initial conditions. Giving:
`DeltaK=1/2m(v_f^2-v_i^2)=1/2*5(16^2-5^2)=5/2(256-25)=577.5N`