If an object with uniform acceleration (or deceleration) has a speed of #12 m/s# at #t=0# and moves a total of 145 m by #t=15#, what was the object's rate of acceleration?

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Answer 1 · 2018-06-20T15:37:10

The deceleration is #=0.31ms^-2#

Apply the equation of motion

#s=ut+1/2at^2#

The initial velocity is #u=12ms^-1#

The distance is #s=145m#

The time is #t=15s#

Therefore,

#145=12xx15+1/2axx15^2#

#1/2a*225=145-180=-35#

#a=-2*35/225=-0.31ms^-2#