# If an object with uniform acceleration (or deceleration) has a speed of 12 m/s at t=0 and moves a total of 14 m by t=12, what was the object's rate of acceleration?

$14 = 12 \times 12 + a \times {12}^{2}$
$a = - \frac{130}{144} = - \frac{65}{72} m {S}^{-} 2$