If an object with uniform acceleration (or deceleration) has a speed of #12 m/s# at #t=0# and moves a total of 48 m by #t=6#, what was the object's rate of acceleration?

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Answer 1 · 2018-03-05T18:26:58

For constant acclertion (#a#) against the direction of motion or deceleration,we can apply,

#s=ut -1/2at^2# where, #u# is the initial velocity and #s# is the displacement in #ts#

Given, #s=48m,t=6s,u=12ms^-1#

so, #a=1.34ms^-2#