# If an object with uniform acceleration (or deceleration) has a speed of 12 m/s at t=0 and moves a total of 48 m by t=6, what was the object's rate of acceleration?

For constant acclertion ($a$) against the direction of motion or deceleration,we can apply,
$s = u t - \frac{1}{2} a {t}^{2}$ where, $u$ is the initial velocity and $s$ is the displacement in $t s$
Given, $s = 48 m , t = 6 s , u = 12 m {s}^{-} 1$
so, $a = 1.34 m {s}^{-} 2$