If an object with uniform acceleration (or deceleration) has a speed of 2 m/s at t=0 and moves a total of 12 m by t=5, what was the object's rate of acceleration?

Dec 12, 2015

$0.16 {\text{m/s}}^{2}$

Explanation:

Use this equation of motion:

$s = u t + \frac{1}{2} a {t}^{2}$

The value of $t = 5$ is used as this is the total time for the journey:

$\therefore 12 = \left(2 \times 5\right) + \left(0.5 \times a \times {5}^{2}\right)$

$\therefore a = \frac{2}{0.5 \times 25} = 0.16 {\text{m/s}}^{2}$