# If an object with uniform acceleration (or deceleration) has a speed of 3 m/s at t=0 and moves a total of 24 m by t=5, what was the object's rate of acceleration?

Feb 3, 2016

$0.72 m {s}^{- 2}$

#### Explanation:

we know that,

$s = u t + \frac{1}{2} a {t}^{2}$

$\mathmr{and} , 24 = 3 \cdot 5 + 0.5 a \cdot {5}^{2}$

$\mathmr{and} , 9 = \frac{25}{2} a$

$a = 0.72 m {s}^{- 2}$