Question

If an object with uniform acceleration (or deceleration) has a speed of `3 m/s` at `t=0` and moves a total of 24 m by `t=5`, what was the object's rate of acceleration?

Answer 1

`0.72ms^(-2)`

Explanation:

we know that,

`s=ut+1/2at^2`

`or,24=3*5+0.5a*5^2`

`or,9=25/2a`

`a=0.72ms^(-2)`