# If an object with uniform acceleration (or deceleration) has a speed of 4 m/s at t=0 and moves a total of 26 m by t=9, what was the object's rate of acceleration?

May 16, 2016

$\gamma = - \frac{20}{81}$
s = s_0+v_0t+1/2 gamma t²
In $t = 0$ the movement begins with ${s}_{0}$ and ${v}_{0} = 4$
After $t = 9$ the object situation is
$26 = 4 \cdot 9 + \frac{1}{2} \gamma {9}^{2}$. Solving for $\gamma = - \frac{20}{81}$