If cot theta = - 2cotθ=2 and cos theta < 0cosθ<0, how do you find sinthetasinθ?

1 Answer
Mar 30, 2018

Start with the identity:

1+ cot^2(theta)=csc^2(theta)1+cot2(θ)=csc2(θ)

Explanation:

Substitute cot^2(theta) = (-2)^2cot2(θ)=(2)2:

1+ (-2)^2=csc^2(theta)1+(2)2=csc2(θ)

5 = csc^2(theta)5=csc2(θ)

Substitute csc^2(theta) = 1/sin^2(theta)csc2(θ)=1sin2(θ)

5 = 1/sin^2(theta)5=1sin2(θ)

sin^2(theta) = 1/5sin2(θ)=15

sin(theta) = +-sqrt5/5sin(θ)=±55

Because we are told that cos(theta) < 0cos(θ)<0 and cot(theta) = -2cot(θ)=2, we know that the sine function must be positive in this quadrant:

sin(theta) = sqrt5/5sin(θ)=55