# If each of the equal angles of an isosceles triangle measure 25 degrees less than twice the vertex angle, what would the vertex triangle measure?

Jan 15, 2016

$46$ degress

#### Explanation:

I assume the question should read "what would the vertex ANGLE measure".

Let the vertex angle $= \theta$
Then each of the other angles equals $\left(2 \theta - 25\right)$

The sum of the angles in a triangle is $180$ degrees

$\therefore \theta + 2 \left(2 \theta - 25\right) = 180$

$5 \theta - 50 = 180$

$\theta = \frac{230}{5} = 46$