Question

If Earth has a mass of 5.972 × 10^24 kg and Mars has a mass of 6.39 × 10^23 kg, and the distance between them is 225 x 10^6 m, with what force does Earth pull on Mars?

Answer 1

This is an application of the Universal Gravitation Equation `F_G=G{m_1m_2}/d^2`

Explanation:

In your case, you are given all the variable and all you need to know is that the Gravitational Constant, `G = 6.67xx10^{-11} {m^3}/{kg*s^2}`

So, `F_G=6.67xx10^{-11}{5.972xx10^24*6.3xx10^23}/{(225xx10^6)^2}`

Then, `F_G=6.67xx10^{-11}{3.82xx10^48}/{(50625xx10^12)}`

`F_G=6.67xx10^{-11}{3.82xx10^48}/{(5.06xx10^16)}`

`F_G=6.67xx10^{-11}*7.55xx10^31`

`F_G=5.04xx10^21`Newtons