If f(x)= 1/x and g(x) = 2e^x -4 , how do you differentiate f(g(x)) using the chain rule?

1 Answer
Nov 5, 2017

-(2e^x-4)(2e^x)

Explanation:

f(g(x))
= f(2e^x-4)
=1 / (2e^x-4)

This can be rewritten as:
(2e^x-4)^-1

Differentiating with respect to x,
-(2e^x-4)(2e^x)