# If f(x)=2x^2+5sqrt(x+2) how do you find f(0)?

$f \left(0\right) = \pm 5 \sqrt{2}$
For $f \left(0\right)$, simply substitute $x = 0$ into the function.
And thus, $f \left(0\right) = 2 {\left(0\right)}^{2} + \pm 5 \sqrt{0 + 2} = \pm 5 \sqrt{2}$