If #f(x)=2x+8# and #g(x)=3x-2#, how do you find #f(g(1))#?

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Answer 1 · 2017-03-12T12:25:02

The answer is #=10#

This is a composition of functions

#f(x)=2x+8#

#g(x)=3x-2#

#f(g(x))=f(3x-2)=2(3x-2)+8#

#=6x-4+8=6x+4#

Therefore,

#f(g(1))=(6*1)+4=10#