If #f(x)=2x+8# and #g(x)=3x-2#, how do you find #f(g(-2))#?

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Answer 1 · 2018-03-02T23:42:48

The result is #-8#.

First, compute #g(-2)#:

#color(white)=>g(x)=3x-2#

#=>g(-2)=3(-2)-2#

#color(white)(=>g(-2))=-6-2#

#color(white)(=>g(-2))=-8#

Now, compute #f(-8)#:

#color(white)=>f(x)=2x+8#

#=>f(-8)=2(-8)+8#

#color(white)(=>f(-8))=-16+8#

#color(white)(=>f(-8))=-8#

The result is #-8#.