If $f(x)=2x+8$ and $g(x)=3x-2$ , how do you find $f(g(-2))$ ?

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Answer 1 · 2018-03-02T23:42:48

The result is $-8$ .

First, compute $g(-2)$ :

$color(white)=>g(x)=3x-2$

$=>g(-2)=3(-2)-2$

$color(white)(=>g(-2))=-6-2$

$color(white)(=>g(-2))=-8$

Now, compute $f(-8)$ :

$color(white)=>f(x)=2x+8$

$=>f(-8)=2(-8)+8$

$color(white)(=>f(-8))=-16+8$

$color(white)(=>f(-8))=-8$

The result is $-8$ .

If f(x)=2x+8f(x)=2x+8 and g(x)=3x-2g(x)=3x-2, how do you find f(g(-2))f(g(-2))?