If #f(x)=2x+8# and #g(x)=3x-2#, how do you find #g(f(1))#?
1 Answer
Jan 31, 2017
Explanation:
To evaluate g(f(1)) , first evaluate f(1) and substitute result into g(x)
#rArrf(color(magenta)(1))=(2xx color(magenta)(1))+8=10#
#rArrg(f(1))=g(color(magenta)(10))=(3xxcolor(magenta)(10))-2=28#
