If #f(x)= 2x - e^x # and #g(x) = 3 x #, how do you differentiate #f(g(x)) # using the chain rule?

1 Answer
Jun 19, 2016

Answer:

#f'(g(x))=6- 3e^(3x)#

Explanation:

#f(g(x))=2*(3x)-e^(3x)#
can be written again
#f(g(x))=6x-e^(3x)#
use chain rule
differentiate "outside" function first, and then differentiate "inside" function
#d/dxf(g(x))#
=#f'(g(x))=6- **3** e^(3x)#
because 3x is "inside" function ,and it also need to differentiate