If $f (x) = 3 x + 4$ $f(x)=3x+4$ and $g (x) = x^{2} - 1$ $g(x)=x^2-1$ , how do you find $f (g (x))$ $f(g(x))$ ?

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If $f (x) = 3 x + 4$ $f(x)=3x+4$ and $g (x) = x^{2} - 1$ $g(x)=x^2-1$ , how do you find $f (g (x))$ $f(g(x))$ ?

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Answer 1 · 2017-01-21T17:01:08

$f (g (x)) = 3 x^{2} + 1$ $f(g(x))=3x^2+1$

Explanation:

Substitute x=g(x) that is $x = x^{2} - 1$ $x=x^2-1$ into f(x).

$\Rightarrow f (g (x)) = f (x^{2} - 1)$ $rArrf(g(x))=f(color(red)(x^2-1))$

$= 3 (x^{2} - 1) + 4$ $=3(color(red)(x^2-1))+4$

$= 3 x^{2} - 3 + 4 = 3 x^{2} + 1$ $=3x^2-3+4=3x^2+1$

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If $f (x) = 3 x + 4$ $f(x)=3x+4$ and $g (x) = x^{2} - 1$ $g(x)=x^2-1$ , how do you find $f (g (x))$ $f(g(x))$ ?

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If $f (x) = 3 x + 4$ $f(x)=3x+4$ and $g (x) = x^{2} - 1$ $g(x)=x^2-1$ , how do you find $f (g (x))$ $f(g(x))$ ?