If $f (x) = 3 x + 4$ $f(x)=3x+4$ and $g (x) = x^{2} - 1$ $g(x)=x^2-1$ , how do you find $g (f (x))$ $g(f(x))$ ?

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If $f (x) = 3 x + 4$ $f(x)=3x+4$ and $g (x) = x^{2} - 1$ $g(x)=x^2-1$ , how do you find $g (f (x))$ $g(f(x))$ ?

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Answer 1 · 2017-05-03T18:23:24

I got: $g (f (x)) = 9 x^{2} + 24 x + 15$ $g(f(x))=9x^2+24x+15$

Explanation:

Here you want the function $g$ $g$ that has "inside" the Variable $f (x)$ $f(x)$ !
So we write the function $g$ $g$ with instead of $x$ $x$ the new variable $f (x)$ $f(x)$ :

$g (f (x)) = {(3 x + 4)}^{2} - 1$ $g(f(x))=(color(red)(3x+4))^2-1$

$g (f (x)) = 9 x^{2} + 24 x + 16 - 1$ $g(f(x))=9x^2+24x+16-1$

$g (f (x)) = 9 x^{2} + 24 x + 15$ $g(f(x))=9x^2+24x+15$

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If $f (x) = 3 x + 4$ $f(x)=3x+4$ and $g (x) = x^{2} - 1$ $g(x)=x^2-1$ , how do you find $g (f (x))$ $g(f(x))$ ?

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If f(x)=3x+4f(x)=3x+4f(x)=3x+4 and g(x)=x^2-1g(x)=x2−1g(x)=x^2-1, how do you find g(f(x))g(f(x))g(f(x))?

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Explanation:

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If $f (x) = 3 x + 4$ $f(x)=3x+4$ and $g (x) = x^{2} - 1$ $g(x)=x^2-1$ , how do you find $g (f (x))$ $g(f(x))$ ?