If #f(x)=3x+4# and #g(x)=x^2-1#, how do you find #g(g(x))#?
1 Answer
Jan 29, 2017
Explanation:
To find g(g(x)), substitute
#x=x^2-1# into g(x)
#g(g(x))=g(color(red)(x^2-1))=(color(red)(x^2-1))^2-1#
#rArrg(g(x))=x^4-2x^2+1-1=x^4-2x^2#
