# If f(x)=3x if x<0, x+1 if 0≤ x≤ 2, and (x-2)^2 if x>2, how do you find f(1)?

$f \left(1\right) = 2$.
$x = 1$ lies in the area of the piecewise function that is represented by $x + 1$. Therefore, $f \left(1\right) = 1 + 1 = 2$.