If #f(x)=abs(x^2-3)#, how do you find f(2)?

1 Answer
Jan 10, 2017


Replace the #x# with the given value of 2, then follow normal order of operations.


#f(2) = |2^2 - 3| = |4-3| = |1|

Since the argument in the absolute value bars is a positive number, they serve no real purpose, and can be removed.

(Had the argument in the bars been -1, the answer would also have been 1, since the absolute value always returns a positive result.)