If #f(x)=mx-2# , #g(x)=(3x+2n)/6# and #(g@f)(x)# is a unit function, what is #m+n# ?

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Answer 1 · 2016-07-14T10:28:31

#m = 0, n = 6->m+n=6#

Supposing that #g@f# to be a unit function is

#(g@f)(x)=1 forall x in RR#

#(g@f)(x) = (3f(x)+2n)/6 = 1/6 (2 n + 3 (m x-2))#

or

#(g@f)(x) = m/2x+n/3-1=1#

then

#m = 0, n = 6#

then #m+n = 6#