If $f(x)=mx-2$ , $g(x)=(3x+2n)/6$ and $(g@f)(x)$ is a unit function, what is $m+n$ ?

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Answer 1 · 2016-07-14T10:28:31

$m = 0, n = 6->m+n=6$

Supposing that $g@f$ to be a unit function is

$(g@f)(x)=1 forall x in RR$

$(g@f)(x) = (3f(x)+2n)/6 = 1/6 (2 n + 3 (m x-2))$

or

$(g@f)(x) = m/2x+n/3-1=1$

then

$m = 0, n = 6$

then $m+n = 6$

If f(x)=mx-2f(x)=mx-2 , g(x)=(3x+2n)/6g(x)=(3x+2n)/6 and (g@f)(x)(g@f)(x) is a unit function, what is m+nm+n ?