Question

If `f(x) =x^2-16` and `g(x)=x+4`, what is `f/g` and its domain?

Answer 1

`(f/g)(x) = (x^2 - 16)/(x + 4)`

`(f/g)(x) = ((x+ 4)(x - 4))/(x + 4)`

`(f/g)(x) = x - 4`

The domain of this linear function, as well as any linear function, is `x in RR`. However, we would have a hole at `(-4, -8)`.

Hopefully this helps!