If #f(x)=x^2 + 2x +3#, then how do you find f(a-1)?

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Burglar Share
May 28, 2016

Answer:

It is enough to substitute #x# with #(a-1)#.

Explanation:

It is enough to write #(a-1)# every time that you read #x#.

#f(a-1)=(a-1)^2+2(a-1)+3#

then it is just a matter of doing a bit of algebra

#f(a-1)=(a-1)^2+2(a-1)+3#
#=a^2-2a+1+2a-2+3#
#=a^2+2#.

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Explanation

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Jim G. Share
May 28, 2016

Answer:

#a^2+2#

Explanation:

Substitute x = a-1 into function.

#rArrf(a-1)=(a-1)^2+2(a-1)+3#

expand brackets and collect like terms.

#rArr(a-1)^2+2(a-1)+3=a^2-2a+1+2a-2+3#

#=a^2+2#

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